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PLEASE I NEED HELP WITH MY MATHS HOMEWORK< I HAVE SO MUCH HOMEWORK DURING THIS QUARANTINE

USE THE IMAGE ATTACHED BELOW TO HELP ME
The diagram shows a square ABCD with sides of length 20cm
It also shows a semicircle and arc of a circle.
AB is the diameter of the semicircle
BD is an arc of a circle with centre A

a) Find the area of the shaded region giving your answer in terms of π
You must show your working,clearly stating the area of the semicircle

PLEASE I NEED HELP WITH MY MATHS HOMEWORK< I HAVE SO MUCH HOMEWORK DURING THIS-example-1
User Omarion
by
5.3k points

2 Answers

5 votes

Answer:

Explanation:

PLEASE I NEED HELP WITH MY MATHS HOMEWORK< I HAVE SO MUCH HOMEWORK DURING THIS-example-1
User Andre Luus
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5.7k points
4 votes

a) The area of the shaded region is 50π.

b)
(Area of the shaded region)/(area of square) = (\pi)/(8) .

Explanation:

Step 1:

The area of a circle
= \pi r^(2).

The area of a semi-circle
= (\pi r^(2) )/(2) .

The area of a quarter-circle
= (\pi r^(2) )/(4) .

The shaded region's area is obtained by subtracting the area of the semi-circle with a radius of 10 cm from the area of a quarter-circle with a radius of 20 cm.

The area of the semi-circle with a radius of 10 cm
= (\pi (10^(2)) )/(2) .

The area of the quarter-circle with a radius of 20 cm
= (\pi (20^(2)) )/(4) .

Step 2:

The area of the shaded region is obtained by subtracting these areas.

The area of the shaded region
= (\pi (20^(2)) )/(4) - (\pi (10^(2)) )/(2) .


(\pi (20^(2)) )/(4) - (\pi (10^(2)) )/(2) = (\pi)/(2) ((20^(2) )/(2) -10^(2) ).


(\pi)/(2) ((20^(2) )/(2) -10^(2) ) = (\pi)/(2) ((400)/(2) -100 ) = (\pi)/(2) (100).


(\pi)/(2) (100) = 50 \pi.

The area of the shaded region is 50π square units.

Step 3:

The area of a square is the square of the side length.

The area of the square
= 20^(2) = 400 square cm.

b)
(Area of the shaded region)/(area of square) =(50\pi)/(400) =(\pi)/(8) .

User Ditoslav
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6.1k points