Question

Compute (2i-6)(5+1) where i=√1

Answer 1

Explanation:

hello :

(2i-6)(5+i)=10i+2i²-30-6i ... i² = -1

(2i-6)(5+i)=10i-2-30-6i = -32+4i

Answer 2

4i - 32

Explanation:

(2i-6)(5+i)

10i - 30 + 2i² - 6i

i=√-1

i² = -1

10i - 30 + 2(-1) - 6i

-30 - 2 + 10i - 6i

-32 + 4i

4i - 32