Answer:
Part 1)
![JL=2√(3)\ units](https://img.qammunity.org/2021/formulas/mathematics/high-school/3k6znofgbmwhye1f8l9vjz1vqaogr72lxs.png)
Part 2) Yes, It is a 30-60-90 triangle
Explanation:
The picture of the question in the attached figure
Part 1) How long is JL?
we know that
In the right triangle JKL
---> by TOA (opposite side divided by adjacent side)
we have
![KL=2\ units](https://img.qammunity.org/2021/formulas/mathematics/high-school/jsawthb7vfevr7so8vlod5gvg281reym5l.png)
![tan(60^o)=√(3)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/bjzkw58p1f2l66d7s1sgxsn1cyvf23bxt8.png)
substitute the given values
![√(3)=(JL)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/p4uju5mhsoq08legwydnj2da6dt55vtet9.png)
![JL=2√(3)\ units](https://img.qammunity.org/2021/formulas/mathematics/high-school/3k6znofgbmwhye1f8l9vjz1vqaogr72lxs.png)
Part 2) This is a 30-60-90 triangle?
Find the measure of angle J
we know that
---> by complementary angles in a right triangle
we have
![m\angle K=60^o](https://img.qammunity.org/2021/formulas/mathematics/high-school/mbjo4ugjh5y737ic2xvz1jrbcp9pvr7d87.png)
substitute
![60^o+m\angle J=90^o](https://img.qammunity.org/2021/formulas/mathematics/high-school/t8g8i7gkfzc7fnplma3k7woza911qc42jm.png)
![m\angle J=90^o-60^o=30^o](https://img.qammunity.org/2021/formulas/mathematics/high-school/t5i82r6igarf62usjfcl2escqm0jhvw98a.png)
therefore
The right triangle JKL is a 30-60-90 triangle