Given:
From the figure, the sides are (2x + 5), (x + 12), (y - 4) and (x + 5)
The sides having lengths (2x + 5) and (x + 12) are equal.
The sides having lengths (y - 4) and (x + 5) are equal.
We need to solve the given figure.
Value of x:
Let us determine the value of x.
Equating the two sides having equal lengths (2x + 5) and (x + 12), we get;
![2x+5=x+12](https://img.qammunity.org/2021/formulas/mathematics/middle-school/871lzwpd49nwvokwrkkm3j541xwo6trgzn.png)
![x+5=12](https://img.qammunity.org/2021/formulas/mathematics/high-school/a9o6ugjwoansqruml3kury2ajtj025p6sg.png)
![x=7](https://img.qammunity.org/2021/formulas/mathematics/high-school/2bnkqxj7yd0fo7vi8japxxe1irbgu1f8vb.png)
Thus, the value of x is 7.
Value of y:
The value of y can be determined by equating the two sides (y - 4) and (x + 5) having equal lengths.
Thus, we have;
![y-4=x+5](https://img.qammunity.org/2021/formulas/mathematics/middle-school/n0x7eka22uwtlsphzwtzmpjekl0u5jq48n.png)
Substituting x = 7, we get;
![y-4=7+5](https://img.qammunity.org/2021/formulas/mathematics/high-school/hc6h6ziodq3p70y66rocs0b8s71ooe9t25.png)
![y=7+5+4](https://img.qammunity.org/2021/formulas/mathematics/high-school/yvvs1e18pnvva8gjbnuqobbaksxajmbgqa.png)
![y=16](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ujy62ukx172neq505zj2eflpjd2n6c9154.png)
Thus, the value of y is 16.
Side lengths of the figure:
The side lengths can be determined by substituting the values of x and y.
Thus, we have;
![2x+5=2(7)+5=19](https://img.qammunity.org/2021/formulas/mathematics/high-school/kr9lc8dasnw4i8ocna5x2pct87c0jb79he.png)
![x+12=7+12=19](https://img.qammunity.org/2021/formulas/mathematics/high-school/mfm2465owukm9yj5z7dfw6n18zqcpq86ki.png)
![x+5=7+5=12](https://img.qammunity.org/2021/formulas/mathematics/high-school/6eoyl99x56jeay2s5zyfuu1t48sve454qw.png)
![y-4=16-4=12](https://img.qammunity.org/2021/formulas/mathematics/high-school/nztzrdslbwbcowms97tlpija3tlulsochi.png)
Thus, the lengths of the figure are 19, 19, 12, 12.