Question

⚠️⚠️A toy car with a mass of 0.65 kg is traveling at a speed of 2.0 m/s. It

collides head on with a 0.55 kg car traveling at a speed of 3.0 m/s in the
opposite direction. The 0.65 kg car bounces straight back with a speed of
1.5 m/s. Find the speed of the 0.55 kg car immediately following the
collision. *
1.1m/s, 2.4m/s, 3.5m/s, 7.1m/s

Answer 1

1.1 m/s

Step-by-step explanation

momentum is conserved, so the total momentum of both cars is the same before and after the collision, where momentum is the product of mass and velocity

`m_(1) v_(1) + m_2v_2=m_1v_3+m_2v_4`

m1 = 0.65 kg

m2 = 0.55 kg

v1 = 2.0 m/s

v2 = -3.0 m/s (negative because moving in opposite direction)

v3 = -1.3 m/s (since it bounces back, this is in the opposite/negative direction)

`m_(1) v_(1) + m_2v_2=m_1v_3+m_2v_4`

`0.65*2+0.55*-3=0.65*-1.5+0.55v_4\\1.3 + (-1.65) = -0.975+0.55v_4\\1.3 - 1.65 + 0.975 = 0.55v_4\\0.625 = 0.55v_4\\v_4 = 1.1`