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How high can a 21 watt motor lift a 10kg package in 6 seconds?

User LiamV
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1 Answer

5 votes

Answer: 1.3 m

Step-by-step explanation:

Given that,

power of motor lift = 21 watts

Mass of package (m) = 10 kg

height (h) = ?

Time (h) = 6 seconds

Since power is the rate of work done per unit time i.e Power is simply obtained by dividing work by time. Its unit is watts.

i.e Power = work / time

[since work = force x distance,

& force = mass x acceleration due to gravity (g)]

Then, Power = (mass x acceleration due to gravity x height) / time

Recall that g has a value of 9.8 m/s²

I.e Power = mgh / t

21 watts = (10 kg x 9.8 m/s² x h) / 6s

21 watts = (98 kgm/s² x h) / 6s

Cross multiply

21 watts x 6s = 98 kgm/s² x h

126 watts•s = 98 kgm/s²•h

Divide both sides by 98 kgm/s²

126 watts•s / 98 kgm/s² = 98 kgm/s²•h/ 98 kgm/s²

1.286 m = h

(Round the 1.286 m to the nearest tenth as 1.3 m)

Thus, the package can go 1.3 metres high

User Alexandre Morgaut
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