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How many moles of Ca(NO3)2 are there in 0.075 L of 0.25 M solution?
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How many moles of Ca(NO3)2 are there in 0.075 L of 0.25 M solution?

How many moles of Ca(NO3)2 are there in 0.075 L of 0.25 M solution?-example-1
User Gghuffer
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1 Answer

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Answer:

.01875 moles Ca(NO3)2

Step-by-step explanation:

To find moles we must cancel Liters using the concentration x volume:

(.25 mol/L) x (.075L) = .01875 moles Ca(NO3)2

User Bacongobbler
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