Question

Q = smT

S water = 4.184 J/g℃
1 calorie = 4.184 J

How much heat, in joules and in calories, is required to raise the temperature of 2.0 L of water from 23 to 100 ℃? Remember, the density of water is 1.0 g/mL.

Answer 1

The joules required to heat 2L of water in a pot from 20 c to the boiling point of water is calculated using the following formula

Explanation:

Q= MC delta T

M = mass = density x volume( 2 x 1000= 2000ml)

M = 1g/ml x2000 ml = 2000g

C = specific heat capacity = 4.18 g/c

delta T = change in temperature = 100 c ( boiling point of water) - 20 c = 80 c

Q is therefore = 2000 g x 4.18 j/g c x 80c = 668800