Answer:
(3) the function is decreasing for all real numbers of x where x< 1.5
Explanation:
The function given in this problem is
![f(x)=(x-4)(x+1)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/jdxkw5x8k74m1gu84jt2m942svr67010hz.png)
which can be rewritten as:
![f(x)=x^2-4x+x-4=x^2-3x-4](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ixsbkdj5m05n9ovn43zk4mgpef0i1fbgd3.png)
A function is:
- Increasing over a certain interval if the first derivative
is positive in that interval
- Decreasing over a certain interval is the first derivative
is negative in that interval
So we start by calculating the first derivative of this function. We get:
![f'(x)=2x^(2-1)-3x^(1-1)=2x-3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/wiklaffvrbl9uzvhg4kil809zrgs34ndp7.png)
This function is positive when:
![2x-3>0\\2x>3\\x>(3)/(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/1cma8b62k0yh4zo8ql2lqgddh1vxwqw33f.png)
Which means, when x > 1.5.
So the function is:
- Increasing for x > 1.5
- Decreasing for x < 1.5
So the correct option is
(3) the function is decreasing for all real numbers of x where x< 1.5