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What is the slope of a trend line that passes through the points (5, 80) and (7, 65)?

Negative StartFraction 15 Over 2 EndFraction
Negative StartFraction 2 Over 15 EndFraction
StartFraction 2 Over 15 EndFraction
StartFraction 15 Over 2 EndFraction

User Manit
by
5.5k points

2 Answers

3 votes

Answer:

-15/2

Just took the test.

User Thomas Dickey
by
5.0k points
5 votes

Answer:

-15/2 or -7.5 or -7½

Negative StartFraction 15 Over 2 EndFraction

Explanation:

Slope or gradient of a line is the ratio of change in y co-ordinates to the change in x co-ordinates.

Therefore;

M=∆y÷∆x

The change in y co-ordinates is given by

∆y=y2-y1

Similarly, change in x co-ordinates is given by

∆x=x2-x1

Given the two points as (5, 80) and (7, 65)

X1=5 Y1=80

X2=7 Y2=65

∆y=65-80=-15

∆x=7-5=2

Hence ∆y÷∆x will be -15÷2=-7.5 or -7½

Negative StartFraction 15 Over 2 EndFraction

User Rajib Chy
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5.6k points