Answer:
Explanation:
f(x)=x^4+3x^2-4
put x²=y
squaring x^4=y²
f(x)=y²+3y-4
=y²+4y-y-4
=y(y+4)-1(y+4)
=(y+4)(y-1)
so f(x)=(x²+4)(x²-1)
=[x²-(-4)](x²-1²)
=[x²-(4i²)](x²-1²)
=[x²-(2i)²](x²-1²)
=(x+2i)(x-2i)(x+1)(x-1)
[∵a²-b²=(a+b)(a-b)]
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