Question

A sample of bromine gas at 79.06 kPa experiences a change in volume from 63.299 L to 69.057 L.

What is the resulting pressure in kilopascals? Pressure 1 x volume 1=pressure 2 x volume 2

Answer 1

74.47 kPa

Step-by-step explanation:

As provided in the question, Boyle's law follows that

Pressure 1 x volume 1=pressure 2 x volume 2

Given that

Pressure 1 =79.06 kPa

volume 1=63.299L

pressure 2=unknown

Volume 2=69.057L

Substituting these into the formula then

79.06*63.299=69.057*P2

Making pressure 2 the subject of the formula

`P_2=\frac {79.06*63.299}{69.057}=72.467945899763\\P_2\approx 74.47kPa`

Therefore, the resulting pressure, rounded off to two decimal places is approximately 74.47 kPa