Question

Armando has some coins in his pocket. 3 dimes 2 quarters 2 pennies 5 nickles What is the probability that he will pull out a nickel, then a quarter, then a nickel if he does not put any of the coins back in his pocket after he selects it?

Answer 1

The probability that he will pull out a nickel, then a quarter, then a nickel is
`(1)/(33)`

Step-by-step explanation:

Given:

Number of dimes = 3

Number of Quarters = 2

Number of pennies = 2

Number of Nickles = 5

Total coins = 3 + 2 + 2 + 5

= 12

Probability that Armando will pull out Nickel first =
`(5)/(12)`

After taking out Nickel, the total number of coins in the pocket will be 11

So,

Probability that he will pull a quarter =
`(2)/(11)`

Total coins remaining = 11 - 1 = 10

Total Nickel remaining = 5 - 1 = 4

Probability that he will take our Nickel =
`(4)/(10) = (2)/(5)`

Total probability =
`(5)/(12) X (2)/(11) X(4)/(10)`

=
`(1)/(33)`