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Solve for the value of x. Show your Solution. ( 5 points ) Given ∆RPA and ∆NUJ, RP = 2× + 5 and

NU = 13



Solve for the value of x. Show your Solution. ( 5 points ) Given ∆RPA and ∆NUJ, RP-example-1
User Chrisheinze
by
2.6k points

2 Answers

22 votes
22 votes

Answer:

x = 4

Explanation:

the point here is congruent triangles.

according to the image,

2x + 5 = 13 <---- subtract constants

2x = 13 - 5 = 8 <--- finalize

2x = 8 <----------- divide both sides by 2

2x / 2 = 8 / 2 <-- finalize

x = 4 <--- answer

User NickW
by
2.8k points
21 votes
21 votes


\qquad\qquad\huge\underline{{\sf Answer}}

As we can see in the given figure, The two triangles are congruent to each other by many criterias, so we can infer that Their corresponding sides are of equal length.

That is :


\qquad \tt \dashrightarrow \:2x + 5 = 13


\qquad \tt \dashrightarrow \:2x = 13 - 5


\qquad \tt \dashrightarrow \:2x = 8


\qquad \tt \dashrightarrow \:x = 8 / 2


\qquad \tt \dashrightarrow \:x = 4

Therefore, value of x is 4

User Sandorfalot
by
2.9k points
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