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the length of a rectangle is 5 less than twice the width.if the perimeter of the rectangle is 146,find the area of the rectangle.

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Answer:

The area of the rectangle is 1222 units²

Explanation:

The formula of the perimeter of a rectangle is P = 2(L + W), where L is its length and W is its width

The formula of the area of a rectangle is A = L × W

∵ The length of a rectangle is 5 less than twice the width

- Assume that the width of the rectangle is x units and multiply

x by 2 and subtract 5 from the product to find its length

W = x

L = 2x - 5

- Use the formula of the perimeter above to find its perimeter

∵ P = 2(2x - 5 + x)

∴ P = 2(3x - 5)

- Multiply the bracket by 2

P = 6x - 10

∵ The perimeter of the rectangle is 146 units

P = 146

- Equate the two expression of P

6x - 10 = 146

- Add 10 to both sides

∴ 6x = 156

- Divide both sides by 6

x = 26

Substitute the value of x in W and L expressions

W = 26 units

∴ L = 2(26) - 5 = 52 - 5

L = 47 units

Now use the formula of the area to find the area of the rectangle

∵ A = 47 × 26

∴ A = 1222 units²

The area of the rectangle is 1222 units²

User Barbaris
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