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13 votes
13 votes
Find the sum of the first 150 positive even integers.

User IMath
by
3.0k points

2 Answers

11 votes
11 votes

Answer:

  • Sum of first 150 positive even integers is 22650

Explanation:

We know that first 150 postive even Integers are 2,4,6,8,10... 300.

Here,

  • First term (a) = 2
  • Comman difference (d) = 4 - 2 = 2
  • Total terms (n) = 150
  • Last term (aₙ) = 300


\\

Substituting values in the formula:


\\ :\implies \sf \: \: S_(n) = (n)/(2) (a + a_(n)) \\ \\


:\implies \sf \: \: S_(n) = (150)/(2) (2 + 300) \\ \\


:\implies \sf \: \: S_(n) = 75(302) \\ \\


:\implies \: \:{ \underline{ \boxed{ \pmb{ \pink { \rm{S_(n) = 22650 }}}}}} \\ \\

  • Sum of first 150 positive even integers is 22650
User Perhapsmaybeharry
by
2.5k points
8 votes
8 votes

Answer:

  • The number series 2, 4, 6 , 8. . . . , 150.
  • The first term (a) = 1
  • The common difference (d) = 4 – 2 = 2
  • Total number of terms (n) = 150
  • last term (an) = 300

Formula for finding sum of nth terms =

n/2 × (a + an)

putting the known values ,

Sum = 150/2 × ( 2+300)

Sum = 75 × 302

Sum of first 150 positive even integers = 22650

User Jtromans
by
2.6k points