Question

3. If 90.0 grams of barium chloride react with sulfuric acid, how many

grams of barium sulfate are produced?
BaCl2 + H250.-- BaSO4 + 2HCI

Answer 1

The answer to your question is 100.8 g

Step-by-step explanation:

Data

mass of Barium chloride = 90 g

mass of Barium sulfate = ?

Balanced chemical reaction

BaCl₂ + H₂SO₄ ⇒ BaSO₄ + 2HCl

Process

1.- Calculate the molar mass of BaCl₂ and BaSO₄

BaCl₂ = 137.3 + (2 x 35.5) = 208.3g

BaSO₄ = 137.3 + 32 + (16 x 4) = 233.3g

2.- Use proportions to find the mass of BaSO₄

208.3 g of BaCl₂ --------------------- 233.3 g of BaSO₄

90 g of BaCl₂ --------------------- x

x = (90 x 233.3) / 208.3

x = 20997/ 208.3

x = 100.8 g

3.- Conclusion

There will be produced 100.8 g of BaSO₄