Question

1. Consider the first six terms of this sequence: 2, 5, 8, 11, 14, 17,........What would

be the 41st term of this sequence? *​

Answer 1

a(41) = 122

Explanation:

Each new term of the given sequence is 3 more than the previous term. Thus, this is an arithmetic sequence with common difference d = 3. Since the first term is 2, the general formula for this arithmetic sequence is a(n) = 2 + 3(n - 1).

For the 41st term of this sequence, a(41) = 2 + 3(41 - 1), or

a(41) = 2 + 120 = 122