Question

Integral of (sin(2x) + cos(2x)) dx=

Answer 1

`\displaystyle \int (\sin 2x + \cos 2x)~ dx\\\\=\displaystyle \int \sin 2x ~dx + \displaystyle \int \cos 2x ~ dx\\\\=-\frac{\cos 2x}2 + \frac{\sin 2x}2 +C\\\\=\frac{\sin 2x - \cos 2x}2+C`