Answer:
A
Explanation:
y = 2e^x
y' = 2e^x
y" = 2e^x
A) (1 - x)(2e^x) + x(2e^x) - (2e^x)
= 2e^x - 2xe^x + 2xe^x - 2e^x
= 2e^x - 2e^x - 2xe^x + 2xe^x
= 0
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