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The gas inside a balloon exerts a pressure of 3atm at 298 K. What is the temperature required to increase the pressure to 6 atm?

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Answer: 596 atm

Step-by-step explanation:

Given that,

Original pressure of balloon P1 = 3atm

Original temperature of balloon T1 = 298K

New pressure of balloon P2 = 6atm

New temperature of balloon T2 = ?

Since pressure and temperature are given while volume is constant, apply the formula for Pressure law

P1/T1 = P2/T2

3 atm / 298K = 6 atm / T2

To get the value of T2, cross multiply

3 atm x T2 = 6 atm x 298K

3 atmT2 = 1788 atmK

Divide both sides by 3 atm

3 atmT2 / 3 atm = 1788 atmK / 3 atm

T2 = 596 atm

Thus, a temperature of 596 atmospheres is required to increase the pressure to 6 atm.

User Somwang Souksavatd
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