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Determine the external concentration of substance

L
that will result in one-half of the maximal entry rate.

User Dranobob
by
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1 Answer

3 votes

Answer:

32 mmol/L

Step-by-step explanation:

Assume you have the following table:


\begin{array}{cc}\textbf{c/mmol$\cdot$L$^{\mathbf{-1}}$} &\textbf{rate/\% of max}\\30 & 45 \\40 & 65 \\\end{array}

Assume the relationship is linear in this concentration range.

The difference between 45 and 65 is 20.

The difference between 45 and 50 is 5.

So, 50 is 5/20 = ¼ the interval.

The corresponding concentration interval should be

¼(40 - 30) = ¼ × 10 =2.5

The concentration corresponding to 50 % of maximum rate is

(30 + 2.5) mmol/L = 32 mmol/L

Determine the external concentration of substance L that will result in one-half of-example-1
User Hugohabel
by
5.2k points