Answer:
Ksp = 2.6935 * 10^-8 mol^4 dm^-12
Step-by-step explanation:
In this question, we are asked to calculate the ksp value for a hypothetical compound having molar solubility of 0.00562
Firstly, let us write the dissociation equation for the hypothetical compound.
MX3 ——-> M+ + 3X-
Let’s get the molar solubilities of the component of dissociation
1 mole of MX3 gave 1 mole of M, this means that the molar solubility of M = 0.00562mol/dm^3
1 mole of MX3 yielded 3 moles of the anion X. This means that the molar solubility of X = 0.00562 * 3 = 0.01686 mol/dm^3
Ksp = [M+][ X-]^3
Ksp = 0.00562 * 0.01686^3
Ksp = 2.6935 * 10^-8 mol^4 dm^-12