Question

A black, totally absorbing piece of cardboard of area a = 2.1 cm2 intercepts light with an intensity of 8.8 w/m2 from a camera strobe light. what radiation pressure is produced on the cardboard by the light?

Answer 1

The value of radiation pressure is
`2.933 * 10^(-8)` Pa

Step-by-step explanation:

Given:

Intensity
`I = 8.8`
`(W)/(m^(2) )`

Area of piece
`A = 2.1 * 10^(-4)`
`m^(2)`

From the formula of radiation pressure in terms of intensity,

`P = (I)/(c)`

Where
`P =` radiation pressure,
`c =` speed of light

We know value of speed of light,

`c = 3 * 10^(8)`
`(m)/(s)`

Put all values in above equation,

`P = (8.8)/(3 * 10^(8) )`

`P = 2.933 * 10^(-8)` Pa

Therefore, the value of radiation pressure is
`2.933 * 10^(-8)` Pa