Question

1. What volume in mL of 28.0M H2SO4 is needed to contain 53.0g of H2SO4?

2. How many grams of calcium hydroxide Ca(OH)2 are needed to make 532.0 mL of a 1.90M solution?

3. If 12 mL of water are added to 124mL of a 0.505M K2SO4 solution, what will the molarity of the diluted solution be?

Answer 1

1. V=19.3 ml

2. mass=74.8g

3. molarity of dilted solution=0.463M

Step-by-step explanation:

1.

First calculate the mole ,

given mass=53g

molecular weight=98g/mole

`mole=(given mass )/(molecular mass)`

mole=0.54

molarity=28M

`molarity =(mole)/(volume in L)`

`28mol/L=(0.54)/(V)`

V=19.285ml

V=19.3 ml

2.

First calculate the mole of calcium hydroxide,

molariy=1.9M

volume=532 ml=0.532L

`mole=molarity* volume in L`

mole=1.01 mol;

`mass = mole* molecular weight`

molecular weight of calcium hydroxide= 74g/mol

mass=74.8g

3.

First calculate the mole before adding water

molariy=0.505M

initial volume=124 ml=0.124L

`mole=molarity* initial volume in L`

mole=0.063 mol;

after dilution volume=136 ml =0.136L

quantity of solute remains unchanged during dilution of solution.

`Molarity of diluted solution=(mole)/(new volume)`

molarity of dilted solution=0.463M