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A tennis ball is struck in such a way that it leaves the racket with a speed of 31.0m/s in the horizontal direction. When the ball hits the court, it is a distance of 13.3m from the racket. Find the height of the racket ball when it left the racket.

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4 votes

Answer:

Height of the racket ball = 0.86 m

Step-by-step explanation:

Given:

Speed of the tennis ball,
v_x= 31 m/s

Distance covered,
R_x = 13.3 m

We have to find the height of the racket ball when it left the racket.

Lets say that the time taken by the ball to hit the court be 't' seconds.


time=(distance)/(speed)


time=(R_x)/(v_x)


t=(13.3\ m)/(31.0\ ms^-^1)


t=0.42 seconds

Now we have to find the height lets say that the height is 'h' meter.


h_y=u_yt + (a_yt^2)/(2) ...second equation of motion


h_y=0 + (gt^2)/(2) ...initial velocity = 0 and acceleration = gravity


h_y=(9.8(0.42)^2)/(2)


h_y=(1.72)/(2)


h_y=0.86 meter.

So the height of the racket ball when it left the racket is of 0.86 m.

User Saeid Doroudi
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