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The volume of a gas is 200 mL at 315.0 kPa pressure. What will the volume be

when the pressure is reduced to 50.0 kPa, assuming the temperature remains
constant?

User Timoteo
by
5.0k points

1 Answer

2 votes

Answer:

1260 mL

Step-by-step explanation:

Given data:

Initial volume of gas = 200 mL

Initial pressure = 315.0 KPa

Final volume = ?

Final pressure = 50.0 KPa

Solution:

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume

Now we will put the values in formula,

P₁V₁ = P₂V₂

315 KPa × 200 mL = 50 KPa × V₂

V₂ = 63000 KPa. mL/ 50 KPa

V₂ = 1260 mL

User Akbar
by
4.7k points