Answer:
B.Yes, regardless of the sign of ΔH, if ΔS is positive, a reaction can be rendered favorable by increasing the temperature
Step-by-step explanation:
Given
∆G= ∆H- T∆S
If ∆G is to remain negative, then irrespective of the sign of ∆H, ∆S must be positive. If ∆S is positive, then increase in T will only lead a more negative value of ∆G. The positive ∆S maintains T∆S at a positive value that can be subtracted from the value of ∆H which is constant.