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8r 2 −5rt+2t 2 8, r, squared, minus, 5, r, t, plus, 2, t, squared from 4r^2+3rt-7t^24r 2 +3rt−7t 2 4, r, squared, plus, 3, r, t, minus, 7, t, squared

1 Answer

5 votes

Answer:


-4r^2 +8rt-9t^2

Explanation:

We want to subtract
8r^2 -5rt+2t^2 from
4r^2+3rt-7t^2

This is given as:


4r^2+3rt-7t^2 -(8r^2 -5rt+2t^2)\\

Open the bracket


4r^2+3rt-7t^2 -8r^2 +5rt-2t^2\\

Collect like terms


4r^2 -8r^2 +5rt+3rt-7t^2-2t^2\\

Simplify


=-4r^2 +8rt-9t^2

Therefore:


4r^2+3rt-7t^2 -(8r^2 -5rt+2t^2) =-4r^2 +8rt-9t^2

User Waleed Ali
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