Full Question
A 52-kg woman and a 85-kg man stand 11 m apart on frictionless ice.
Each person holds the end of a rope and the man pulls on the rope so that he moves toward the woman. How far will the man have moved when he collides with the woman (in meters)
Answer:
4.14m
Step-by-step explanation:
Given
m = mass of the woman = 52kg
M = Mass of the man = 86kg
Taking the position of the woman as the origin
r = position of the woman = 0m
R = position of the man = 11m
d = Distance between them = 11m
First we need to calculate their centre of mass (COM)
this is calculated by
Rm = (mr + MR)/(m + M)
By substituton
Rm = (52(0) + 86(11))/(52 + 86)
Rm = 6.86m
Collision will happen between the woman and the man at there centre of mass.
So, the man will move a distance of (11m - 6.86m)
Distance moved by the man = 4.14m