19.8k views
1 vote
A 0.674\,\text M0.674M0, point, 674, start text, M, end text cobalt(II) chloride (\text{CoCl}_2CoCl 2 ​ start text, C, o, C, l, end text, start subscript, 2, end subscript) solution is prepared with a total volume of 0.0750\,\text{L}0.0750L0, point, 0750, start text, L, end text. The molecular weight of \text{CoCl}_2CoCl 2 ​ start text, C, o, C, l, end text, start subscript, 2, end subscript is 128.9\,\dfrac{\text{g}}{\text{mol}}128.9 mol g ​ 128, point, 9, start fraction, start text, g, end text, divided by, start text, m, o, l, end text, end fraction.

User Taterhead
by
8.4k points

1 Answer

6 votes

Answer:

The mass of this CoCl2 sample is 6.516 grams

Step-by-step explanation:

Step 1: Data given

Molarity of a cobalt(II) chloride (CoCl2) solution is 0.674 M

Volume of the solution is 0.0750 L

The molecular weight of CoCl2 is 128.9 g/mol

Step 2: Calculate moles CoCl2

Moles CoCl2 = molarity CoCl2 solution * volume solution

Moles CoCl2 = 0.674 M * 0.0750 L

Moles CoCl2 = 0.05055 moles

Step 3: Calculate mass of the CoCl2 sample

Mass CoCl2 = moles CoCl2 * molar mass CoCl2

Mass CoCl2 = 0.05055 moles * 128.9 g/mol

Mass CoCl2 = 6.516 grams

The mass of this CoCl2 sample is 6.516 grams

User Maarten Bicknese
by
9.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.