Question

Determine the volume of Fe(NO3)3 stock solution needed to prepare a dilute solution (left side), then decide what volume of dilute solution should be prepared (right side)

Answer 1

Here's what I get

Step-by-step explanation:

Assume you want to use 0.5 mL of a stock solution with a concentration of 0.2 mol·L⁻¹.

You want to prepare a 0.002 mol·L⁻¹ solution.

1. Moles of Fe(NO₃)₃

`\text{Moles of Fe(NO$_(3)$})_(3) = \text{0.5 mL stock} * \frac{\text{0.2 mmol Fe(NO$_(3))$}_(3)}{\text{1 mL stock}}\\\\= \text{0.1 mmol Fe(NO$_(3))$}_(3)`

2. Volume of dilute solution

`V = \text{0.1 mmoL Fe(NO$_(3))$}_(3)* \frac{\text{1 mL solution}}{\text{0.002 mmoL Fe(NO$_(3))$}_(3)}= \textbf{50 mL solution}`