Question

A one-piece cylinder has a core section protruding from the larger drum and is free to rotate around its central axis. A rope wrapped around the drum of radius 1.39 m exerts a force of 3.34 N to the right on the cylinder. A rope wrapped around the core of radius 0.48 m exerts a force of 8.52 N downward on the cylinder.What is the magnitude of the net torque acting on the cylinder about the rotation axis? Answer in units of N ∗ m.

Answer 1

Step-by-step explanation:

Torque created by force 3.34N

= 3.34 x 1.39 = 4.64 N.m

This torque is acting in clockwise direction .

Torque created by force 8.52 N

8.52 x .48

= 4.09 N.m

The force of 8.52 N is acting downward . It may turn the cylinder in clockwise or anticlockwise direction . So we shall consider both the possibilities.

If it rotates the cylinder in clockwise direction

Total torque = 4.64 + 4.09

= 8.73 Nm

If it rotates the cylinder in anticlockwise direction

Total torque = 4.64 - 4.09

= .55 Nm

Net torque will be in clockwise direction.