Answer:
b =
= 4.47
Explanation:
The Pythagorean Theorem is
![a^(2)+b^(2) = c^(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/sqygwx40crjm6nljx3j8fshy88cpdp4pkg.png)
Let's say a= 2, b= x, and c = 4
Since we need to find the value of x, we will rearrange our equation
![a^(2) + c^(2) = b^(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/nr4ppj0lpyl56bjk1tqynv2th1pjpcrgn4.png)
Now, we substitute plug in the numbers for the values
![(2)^(2) + (4)^(2) = b^(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/3txjujrbjn2wkl1x1pvj8kzrfdhua4t24b.png)
Then, find
and
![(4)^(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/i5x7dqh31ub10qsh3w6ft985aqulcna7dc.png)
![(2)^(2) = 4](https://img.qammunity.org/2021/formulas/mathematics/high-school/rvuy5u913wre96eiquo608zmw20kzrfvuw.png)
![(4)^(2) = 16](https://img.qammunity.org/2021/formulas/mathematics/high-school/ykbvkk99ag6bedlodsorgwlmi4eriudew8.png)
4 + 16 =
![b^(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/oau7saf5rpil53q02wg0vrlk1rczrycs5h.png)
Add 4 and 16
4 + 16 = 20
20 =
![b^(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/oau7saf5rpil53q02wg0vrlk1rczrycs5h.png)
We still need to find what b is by itself, we need to get rid of the exponent.
So, we need to take the square root of both sides.
![√(20) = √(b)](https://img.qammunity.org/2021/formulas/mathematics/high-school/mfsy13l9f2wmcxe8053ogjhiwr4jvaon5q.png)
![√(20) = 2√(5)](https://img.qammunity.org/2021/formulas/mathematics/high-school/el5wbnv217yzaeprk5eu649ah54gbbnqa7.png)
b =
= 4.47
And that would be your answer