Question 1

Solve for x with steps

logb(8)+logb(x^2)=logb(x)

Question 2

Answer:

x=(1)/(8)

Explanation:

$\log _b\left(8\right)+\log _b\left(x^2\right)=\log _b\left(x\right)$

$\log _b\left(8\right)+2\log _b\left(x\right)=\log _b\left(x\right)$

$\log _b\left(8\right)+2\log _b\left(x\right)-\log _b\left(8\right)=\log _b\left(x\right)-\log _b\left(8\right)$

$2\log _b\left(x\right)=\log _b\left(x\right)-\log _b\left(8\right)$

$2\log _b\left(x\right)-\log _b\left(x\right)=\log _b\left(x\right)-\log _b\left(8\right)-\log _b\left(x\right)$

$\log _b\left(x\right)=-\log _b\left(8\right)$

$\log _b\left(x\right)=-3\log _b\left(2\right)$

$x=b^(-3\log _b\left(2\right))$
$x=b^(-3\log _b\left(2\right))$

$b^(-3\log _b\left(2\right))$

$=\left(b^(\log _b\left(2\right))\right)^(-3)$

=2^(-3)

=(1)/(8)

x=(1)/(8)

Please log in or register to add a comment.

Please log in or register to answer this question.