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Circle O is shown. Tangents X Z and Y Z intersect at point Z outside of the circle. The first arc formed is arc b, and the second arc formed is arc a.

Which equation is correct regarding the diagram of circle O?

m∠XZY = One-half(a + b)
m∠XZY = One-half(a – b)
m∠XOY = One-half(a + b)
m∠XOY = One-half(a – b)

User Cyndy
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2 Answers

2 votes

Final answer:

m∠XOY = One-half(a – b). The equation that is correct regarding the diagram of circle O is m∠XOY = One-half(a - b). Tangents XZ and YZ intersect at point Z outside of the circle, forming equal angles. The lengths of arcs a and b are also equal, allowing us to use the equation to find the measure of ∠XOY.

Step-by-step explanation:

The equation that is correct regarding the diagram of circle O is m∠XOY = One-half(a - b).

Tangents XZ and YZ intersect at point Z outside of the circle. The angles formed at Z, denoted as ∠XZY, ∠XOY, ∠YOZ, and ∠XOZ, are equal in measure. Since both arcs a and b are subtended by the same angle, ∠XZY, they are also equal in measure. Therefore, we can say that the length of arc a is equal to the length of arc b.

Since the lengths of arcs a and b are equal, we can use the equation m∠XOY = One-half(a - b) to find the measure of ∠XOY. This equation represents the fact that the measure of ∠XOY is half the difference between the lengths of arcs a and b.

User Latze
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4.8k points
3 votes

Answer:

m∠XZY = One-half(a – b)

Step-by-step explanation:

User Josh Allen
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5.5k points