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The gas pressure in an oxygen tank is 3.90 atm at a

temperature of 298 K. If the pressure decreases to 3.20 atm,
what is the temperature of the gas in kelvin?

User John Jesus
by
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1 Answer

3 votes

Answer:

The answer to your question is Temperature 2 = 244.5°K

Step-by-step explanation:

Data

Pressure 1 = 3.90 atm

temperature 1 = 298°K

Pressure 2 = 3.20 atm

temperature 2 = ?

Process

1.- Use the Gay-Lussac law to solve this problem

Pressure 1/Temperature 1 = Pressure 2/Temperature 2

-Solve for Temperature 2

Temperature 2 = Temperature 1 x Pressure 2 / Pressure 1

-Substitution

Temperature 2 = 298 x 3.20 / 3.90

-Simplification

Temperature 2 = 953.6 / 3.90

-Result

Temperature 2 = 244.5°K

User Forrert
by
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