Question

The fundamental frequency of a resonating pipe is 150 Hz, and the next higher resonant frequencies are 300 Hz and 450 Hz. From this information, what can you conclude

Answer 1

Step-by-step explanation:

In case of open organ pipe ,

for fundamental note 2l = wavelength

frequency n = V / Wave length , V is velocity of sound.

f₁ = V / 2I

for first overtone note 2l /2 = wavelength

wavelength = l

frequency = V / wavelength

f₂ = V / l

for second overtone note 2l /3 = wavelength

wavelength = 2l /3

frequency = V / wavelength

f₃ = 3V /2l

f₁ : f₂ : f₃ : : 1 : 2 : 3

In case of closed organ pipe ,

for fundamental note l = 4 x wavelength

frequency n = V / Wave length , V is velocity of sound.

f₁ = V / 4 I

for first overtone note l / = 3 wavelength / 4

wavelength = 4 l / 3

frequency = V / wavelength

f₂ =3 V /4 l

for second overtone note l = 5 wavelength /4

wavelength = 5l /4

frequency = V / wavelength

f₃ = 5 V /4 l

f₁ : f₂ : f₃ : : 1 : 3 : 5.

In case of open organ pipe , frequencies are in any integral ratio.

In case of closed organ pipe , frequencies are only in odd multiple

Since the given ratio are in any integral , the organ pipe must be open organ pipe.