Question

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Answer 1

Given:

Exponential functions

`2^x`,
`3\cdot 2^x` and
`2^(3x)`

To find:

The value of a, b, c, d, e and f.

Solution:

Substitute x = 0 in
`2^x`.

`a=2^0`

a = 1 (∵
`a^0=1`)

Substitute x = 0 in
`3\cdot 2^x`.

`b=3\cdot 2^0`

`b = 3\cdot 1` (∵
`a^0=1`)

b = 3

Substitute x = 0 in
`2^(3x)`.

`c=2^(3\cdot 0)`

`c= 2^(0)` (∵
`a^0=1`)

c = 1

Substitute x = 1 in
`2^x`.

`d=2^1`

d = 2

Substitute x = 1 in
`3\cdot 2^x`.

`e=3\cdot 2^1`

`e = 3\cdot 2`

e = 6

Substitute x = 1 in
`2^(3x)`.

`f=2^(3\cdot 1)`

`f= 2^(3)`

f = 8

Hence a = 1, b = 3, c = 1, d = 2, e = 6 and f = 8.