the final speed in m/s of the 10.0 kg is 2.53 m/s .
Explanation:
Here we have , A 10.0 kg and a 2.0 kg cart approach each other on a horizontal friction less air track. Their total kinetic energy before collision is 96 ). Assume their collision is elastic. We need to find What is the final speed in m/s of the 10.0 kg mass if that of the 2.0 kg mass is 8.0 m/s . Let's find out:
We know that in an elastic collision :
⇒ Total kinetic energy before collision = Total kinetic energy after collision
⇒
![96 = (1)/(2)M_1(v_1)^2 + (1)/(2)M_2(v_2)^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/bdi2yh16wsv1jc9a9zgfdxk8mgdviyhlct.png)
⇒
![96 = (1)/(2)(10)(v_1)^2 + (1)/(2)(2)(8)^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/pbrsrq6ssf9ehddpyryk7ns71johxmjw7m.png)
⇒
![96=5(v_1)^2 + 64](https://img.qammunity.org/2021/formulas/mathematics/middle-school/jopnb7iw3bkoeg5rwg28u7q9v7l0u6v31j.png)
⇒
![5(v_1)^2 =32](https://img.qammunity.org/2021/formulas/mathematics/middle-school/2xu1mio58v353vmrcmxpz39nxqfghwwrgj.png)
⇒
![(v_1)^2 =6.4](https://img.qammunity.org/2021/formulas/mathematics/middle-school/w7xy9h35h1iolpllstdxf60lszdkwxvfjd.png)
⇒
![v_1 =2.53 m/s](https://img.qammunity.org/2021/formulas/mathematics/middle-school/creoq11pu2bntq4dmdndvxn0hsrmree5x2.png)
Therefore , the final speed in m/s of the 10.0 kg is 2.53 m/s .