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Write an equation of the line that passes through the given point and has the given slope. 2. (3, -2); slope 1/3

2 Answers

1 vote

Final answer:

The equation of the line passing through the point (3, -2) with a slope of 1/3 is y + 2 = (1/3)(x - 3), which simplifies to y = (1/3)x - 1.

Step-by-step explanation:

To write an equation of a line that passes through a specific point and has a given slope, we can use the point-slope form of a line's equation, which is expressed as:

y - y1 = m(x - x1),

where (x1, y1) is the point the line passes through and m is the slope. For the point (3, -2) with a slope of 1/3, the equation becomes:

y + 2 = (1/3)(x - 3).

We can also convert this to the slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept. Distributing the slope on the right side and moving terms around, we get:

y = (1/3)x - 1.

The y-intercept (b) of this line is -1, and as expected, the slope is 1/3, indicating a rise of 1 on the vertical axis for every increase of 3 on the horizontal axis.

User Stepan
by
3.9k points
2 votes

Answer:

y= 1/3 x -3

Step-by-step explanation:

y-y1=m(x-x1)

m= slope = 1/3

(3,-2) = (x1, y1)

plug in the values

y+2= 1/3 (x-3)

y+2= 1/3 x - 1

y= 1/3 x -3

User Thai Nguyen Hung
by
3.6k points