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(x+7)^2+9=0

Find x with quadratics

2 Answers

0 votes

Answer:

x = -7 + 3i, -7 - 3i

Explanation:

(x + 7)² + 9 = 0

(x + 7)² = -9

(x + 7) = +- 3i

x + 7 = 3i

x = -7 + 3i

x + 7 = -3i

x = -7 - 3i

x = -7 +- 3i

User Rob Alsod
by
8.7k points
2 votes

Answer:

x = -7 ±3i

Explanation:

(x+7)^2+9=0

Subtract 9 from each side

(x+7)^2+9-9=0-9

(x+7)^2=-9

Take the square root of each side

sqrt((x+7)^2) = ±sqrt(-9)

We know sqrt(ab) = sqrt(a) sqrt(b)

x+7 = ±sqrt(-1) sqrt(9)

We know that sqrt(-1) is the imaginary number i

x+7 = ±i *3

x+7 =±3i

Subtract 7 from each side

x+7-7 = -7 ±3i

x = -7 ±3i

User Vmatyi
by
7.8k points

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