Question

In one circuit, the terminals are at 2 point.

98 V and 100 V. In
a second circuit, they are at 2 V and 6 V. Which
do you think
produces a stronger electric field, and why?​

Answer 1

The second one, because the potential difference is larger

Step-by-step explanation:

For a uniform electric field, the relationship between potential difference and strength of the electric field is:

`\Delta V = Ed` (1)

where

`\Delta V` is the potential difference

E is the strength of the electric field

d is the distance between the two points considered

In this problem, we have:

`\Delta V=100-98=2 V` for the first circuit

`\Delta V=6-2 = 4 V` for the second circuit

From eq(1), we see that the strength of the electric field is directly proportional to the potential difference.

Therefore, if the value of d (distance between the two terminals) is the same in the two circuits, then we can say that the electric field will be stronger in the second circuit, since the potential difference is larger.