Question

A submersible vessel was

lowered 6 meters from its start
position and raised 50 meters.
The vessel then lowered itself 5.5
meters each hour for 7 hours.
How many meters is the vessel
from its start position?

Answer 1

5.5 meters above start position.

Explanation:

-Let X be the start position.

#Total distance below the start position is calculated as:

`d_(down)=6+5.5* 7\\\\=44.5\ m`

#Total distance above the start position X:

`d_(up)=50\ m`

#Distance above/below start position is:

`d=X-d_(down)+d_(up)\\\\=X-44.5+50\\\\d=X+5.5\ m`

Hence, The vessel is 5.5 meters above the start position