Question

A model of a pyramid being built for the San Antonio Zoo enclosed butterfly exhibit has a right triangular base. If the two legs of the triangular base measure 20 feet and 60 feet, how long is the hypotenuse?

Answer 1

63.245 feet.

Explanation:

Given:

A model of a pyramid being built for the San Antonio Zoo enclosed butterfly exhibit has a right triangular base.

If the two legs of the triangular base measure 20 feet and 60 feet.

Question asked:

How long is the hypotenuse? ( Let
`h` )

Solution:

Here base and height of a right angled triangle is given and we have to find the longest side that is hypotenuse.

As we know:

By Pythagoras Theorem:

Square of hypotenuse = Square of base + Square of height of right angled triangle

`h^(2) =20^(2) +60^(2) \\h^(2) =400 +3600\\h^(2) =4000\\\\Taking\ root\ both\ sides\\\\ \sqrt[2]{h^(2) } =\sqrt[2]{4000} \\ \\ h=63.245\ feet`

Thus, hypotenuse of a right triangular base is 63.245 feet.