Question

Patients suffering from respiratory disorders are often treated in oxygen tents in which the atmosphere is enriched in oxygen. WHat id the partial pressure of O2 in an oxygen tent consisting of 45% 02 for an atmospheric pressure of 753 mmHg?

Answer 1

Answer: The partial pressure of oxygen gas in an oxygen tent is 338.85 mmHg

Step-by-step explanation:

To calculate the partial pressure of oxygen gas, we use the equation given by Raoult's law, which is:

`p_(O_2)=p_T* \chi_(O_2)`

where,

`p_(O_2)` = partial pressure of oxygen gas = ? mmHg

`p_T` = total pressure = 753 mmHg

`\chi_(O_2)` = mole fraction of oxygen gas = 0.45

Putting values in above equation, we get:

`p_(O_2)=753mmHg* 0.45\\\\p_(O_2)=338.85mmHg`

Hence, the partial pressure of oxygen gas in an oxygen tent is 338.85 mmHg