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How much energy is absorbed with radiation of wavelength of 200 nm?

User Vzsg
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1 Answer

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Answer:

E = 0.09 × 10⁻¹⁷J

Step-by-step explanation:

Given data:

wavelength of radiations = 200 nm (200× 10⁻⁹ m)

Energy absorbed = ?

Solution:

Formula:

E = hc/λ

h = 6.63× 10⁻³⁴ Js

c = 3 × 10⁸ m/s

Now we will put the values.

E = 6.63× 10⁻³⁴ Js × 3 × 10⁸ ms⁻¹ / 200× 10⁻⁹ m

E = 19.89 × 10⁻²⁶ J / 200× 10⁻⁹

E = 0.09 × 10⁻¹⁷J

User Yechabbi
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