Question

What is the value of the expression x^2y–y+xy^2–x for x=4 and y=0.25?

Answer 1

0 (zero)

Explanation:

`{x}^(2) y - y + x {y}^(2) - x \\ = {4}^(2) * 0.25 - 0.25 + 4 * {0.25}^(2) - 4 \\ = 16 * 0.25 - 0.25 + 4 * 0.0625- 4 \\ = 4 - 0.25 + 0.25 - 4 \\ = 0 \\ \\ \purple {\boxed{ \bold{ \therefore \: {x}^(2) y - y + x {y}^(2) - x = 0}}}`