Final answer:
The electron configuration of Au3+ is [Xe]4f^145d^10.
Step-by-step explanation:
The electronic configuration of Au3+ can be determined by looking at the electron configuration of neutral gold (Au). The electron configuration of neutral gold is [Xe]6s^14f^145d^10. When gold loses three electrons to become Au3+, the three electrons are removed from the 6s orbital. Therefore, the electron configuration of Au3+ is [Xe]4f^145d^10.