Question

The value of ksp for srso4 is 2.8x10-7. What is the solubility of srso4 in moles per liter?

Answer 1

`S=4.47* 10^(-4)mol/L`

Step-by-step explanation:

first write the balance chemical reaction:

`SrSO_4 \rightleftharpoons Sr^(2+) + SO_4^(2-)`

Lets assume that solubilty=S:

`[Sr^(2+)] =S;`

`[SO_4^(2-)] =S;`

`Ksp =[Sr^(2+)] [SO_4^(2-)]`

`Ksp=S* S`

`S=√(Ksp)`

`S=\sqrt{2.8 * 10^(-7)}`

`S=4.47* 10^(-4)mol/L`